
Exercises 295
(b) U(z)=U
l
(2z-z
2
), 0<z<l,
show that no critical level exists.
[Hint: assume that a critical level does exist, use the definition
(3.129) and then show that the only solutions are not critical.]
Q3.47
 Burns condition with critical level
 I. Show that, for 0 < d < 1, the
Burns condition for the model profile
d<z< 1
0 <z < d
where U\ is a constant, gives rise to three solutions for c, one of
which corresponds to a critical level.
Q3.48 Burns
 condition
 with critical level II. Show that the conditions
described in Q3.47 obtain also for the model profile
U
u
 d<z<l
U
{
(2dz-z
2
)/d\
 0<z<d.
Q3.49
 Generalised
 Burns
 condition.
 Show that the generalised Burns
condition, (3.136), has a solution
k(0) = a
 cos 0
 +
 b(a)
 sin 0,
where a is a parameter, and b(a) is to be determined.
Q3.50
 Generalised Burns
 condition for
 oblique
 waves. Determine the gen-
eralised Burns condition, (3.136), for plane oblique waves; that
is,
 k(0) =
 1
 and 0 =
 9Q
 = constant. In the case U = U
o
= constant, find the speed of the wave.
Q3.51
 Generalised
 Burns
 condition
 for linear shear. Determine k(0),
using the method of Q3.49, for the case of a linear shear
U(z) =U
0
 + (U
{
 -
 U
0
)z
9
 0 < z < 1.
[Note: You are advised to make a convenient choice for
 c;
 see
how we obtained (3.138).]
Q3.52 Singular
 solution.
 Derive the solution (3.140) from the general
solution (3.139), using standard methods.
[Note: These ideas are described in any good text on (ordinary)
differential equations, for example Forsyth (1921) or Piaggio
(1933).]
Q3.53
 Variable coefficients
 ->
 cKdV.
 Show that the variable coefficient
KdV equation, (3.148), transforms to the concentric KdV
equation, (3.34), for //, where