
1158.4  Oxidation Reactions Involved in Firework
8.4   Oxidation Reactions Involved in Firework
The last, perhaps most  crucial  and difficult, issue is  why  potassium  “nitrate” or 
potassium “perchlorate” does what it does, i.e., oxidizes something else. As implied 
here,  nitrate  or  perchlorate,  not  potassium,  is  the  oxidizing  agent.  What  is  the 
 “oxidation” anyway? Let us begin from the basics. As we argued (Chap. 19), some 
atoms  hold  their  electrons  more  tightly  than  others  do.  This  tendency  is  called 
“electronegativity.” It is a measure of how strongly an atom (actually its nucleus) 
attracts electron(s) around it. Fluorine (F) has the highest electronegativity, and the 
next is oxygen (O). F has a strong tendency to become F
−
 by attracting one electron. 
Now let us look at nitrate NO
3
−
, a combination of nitrogen and oxygen. Oxygen is 
more electronegative than nitrogen, and oxygen becomes  more  comfortable in  a 
 compound with two more electrons than its neutral atom has, i.e., O
2−
. If this is so, 
then nitrogen in nitrate should carry formally +5 electric charge [i.e., 3 × (−2) (from 
three  O
2−
)+(+5) = −1 = the  overall  charge].  The  oxidation  number  of  nitrogen  in 
nitrate is said to be +5 in this case [and by the way, the oxidation number of oxygen 
in nitrate (and other compounds) is −2] (see also Sect. 3.2.1).
OK so far? Since the nitrogen carries a +5 electric charge in nitrate, you have to 
remove five electrons from a neutral nitrogen atom in order to create it. This requires 
a lot of energy, because an electron is attracted by the positive nucleus, and you have 
to pull them apart with force. “+5” state is called “+5 oxidation state,” as removal of 
electron(s) from a chemical entity is called “oxidation” (we used “+V” instead of +5 
in some other chapters). This implies that the +V (+5) oxidation state of nitrogen in 
nitrate is not very stable, because you have brought it to that state by expending a lot 
of energy. Anything that is in a rather unstable state wants to become more stable. 
This is one of the most basic rules of the physical world. In this case, the nitrogen (in 
V oxidation state) wants to gain electron(s) to become lower oxidation states, for 
example,  the  zero  oxidation  state,  which  is  N
2
  molecule. This can  happen  when 
the  nitrate  comes  into  contact  with  a  compound  which  can  provide  that  elec-
trons. Charcoal and sulfur that are mixed with potassium nitrate are two such sub-
stances. Charcoal is essentially carbon; C can readily give up electrons to become 
nominally +4 (IV), if it can combine two of O
2−
 and forms carbon dioxide, CO
2
. In 
this process, nitrate has gotten electrons from C and turns into N
2
. The process in 
which a compound removes electron(s) from another is defined as “oxidation.” You 
can say that nitrate oxidizes carbon and hence acts as an “oxidizing agent” or “oxi-
dant.” From the carbon’s point of view, it has given electron(s) to nitrate. This pro-
cess, giving electron(s) is called “reduction,” and it can be said that carbon reduces 
nitrate and hence carbon in this case is a “reducing agent” or “reductant.” As you see, 
oxidation and reduction always take place simultaneously; it is like a head and tail of 
a coin. Similar reactions occur between nitrate and sulfur; sulfur will become sulfur 
dioxide SO
2
 and sulfate, SO
4
2−
. It must be noted that nitrate is a very strong oxidizing 
agent, as the nitrogen in nitrate is in such a high oxidation state and hence has a very 
strong tendency to gain electron(s) from other compounds. You may have been con-
fused by now. If so, read this paragraph and the last once more slowly and carefully.