
//FS2/CUP/3-PAGINATION/SDE/2-PROOFS/3B2/9780521873628C11.3D
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157
– [149–162] 13.3.2008 11:19AM
The Anderson criteria are derived from two
basic principles: (i) there are no stresses, normal
or shear, across a free horizontal surface, and (ii)
the largest shear stress occurs across planes
between the directions of maximum and mini-
mum principal stress. The existence of the free
surface requires that one of the principal stress
directions be vertical, normal to the surface. This
applies not just to the surface itself but to all
depths much smaller than the horizontal scale
over which the stresses are averaged, and it is
therefore a constraint on theories of the causes
of geologically observed surface faults. Thus, the
other two principal stresses are horizontal and
there are only three ways in which they can be
oriented. The vertical stress may be the direction
of maximum,
1
, intermediate,
2
, or minimum
principal stress,
3
, and in each case the other
two principal stresses are the horizontal stresses.
As generally applied, the principal stresses are
converted to the rock mechanics convention
with compression positive. With this convention,
the ranking
1
>
2
>
3
corresponds to the most
compressive to least compressive stress.
In a region of compression,
1
and
2
are both
horizontal, with
3
vertical, and thrust (reverse)
faulting (Fig 11.7) occurs. Extension, in which
both horizontal stresses are smaller than the
vertical (and are negative at the surface), causes
normal faulting (Fig. 11.7). Strike-slip faulting
(Fig. 11.7) occurs when the maximum and mini-
mum stresses are horizontal.
An unconfined rock will fail when subjected
to shear stress greater than its internal strength,
S
0
. The failure usually takes the form of relative
motion across a plane that is oriented in the
direction of maximum shear, i.e. at 458 to the
maximum and minimum principal stresses. At
depth, rocks are more resistant to shear failure
because they are subjected to confining pressure
of the overburden. In addition to overcoming
intrinsic internal strength, shears must be large
enough to overcome frictional effects from the
overburden pressure. The frictional stress is
equal to the product of normal stress,
n
, across
a fault plane (with compression taken as posi-
tive) and a friction coefficient. The failure plane
is then not the 45
o
plane of maximum shear,
because the frictional stress is reduced by
turning the normal to the failure plane towards
the axis of minimum stress. This occurs at an
angle such that the reduction in shear stress is
compensated by a reduction in the normal stress.
Coulomb’s equation describes this process and
gives the condition for failure as
¼
f
n
þ S
0
; (11:36)
where t is the limiting shear stress at which fail-
ure occurs,
f
is the friction coefficient, and S
0
is
the internal strength or cohesion. The straight
line in Fig. 11.6(a) gives the failure criterion
(Eq. (11.36)), which lies tangent to the limiting
Mohr circle at the point of failure. The rock is
stable for stress fields having circles that lie
below the failure line. As Fig. 11.6(c) illustrates,
increasing pressure stabilizes against failure
because larger shears are required to generate
Mohr circles that intersect the failure criterion.
From laboratory observations, Byerlee (1978)
found that a value
f
¼0.6 to 0.85 applies to many
common rock types. The lower value applies to
wet rock or rock under high confining pressure
and the upper value to dry rock at low confining
pressure. Equation (11.36), known as Byerlee’s
law, is the equation of a straight line (a better
approximation is a convex curve) that is plotted
on the Mohr diagram to describe conditions for
failure. At the point of failure, 2 of Eq. (11.30) is
an obtuse angle. Therefore, the angle, ,between
the normal to the plane of failure and maximum
principal stress direction is greater than 458.The
slope of the failure line is tan ,where is
referred to as the angle of internal friction, so that
f
¼ tan : (11:37)
Then from Fig. 11.6(a),
2 ¼
p
2
þ : (11:38)
In structural geology one is interested in , the
angle between the dip of the fault plane and
1
,
which is the complement of . Then
¼
p
2
¼
1
2
tan
1
ð1=
f
Þ: (11:39)
For
f
¼0.85, ¼24.88. In general, failure planes
are predicted to occur at small angles to the
directions of maximum principal stress.
11.5 CRUSTAL STRESS AND FAULTING 157