
57. (a) They would have to talk more than 6 months.
(b) They are saving between 42 and 60 dollars per month,
not counting the up-front fees to switch.
59. 1  x  19 and y  20  x
61. 10  x  35 63. 1  t  4 65. 2  t  2.25
67. (a) x
2
 x when 0  x  1 and x
2
 x when x  0 or x  1.
(b) If c is nonzero and c  1, then either 0  c  1 or 1
 c  0 (which is equivalent to 1 c  0). If 0  c
 1, then c  c and c is a solution of x
2
 x by part (a),
so that c
2
 c  c. If 1 c  0, then c c,
which is a solution of x
2
 x by part (a), so that c
2
 (c)
2
 (c)  c.
(c) If c  1, then either c 1 or c  1. In either case, 
c is a solution of x
2
 x by part (a).
69. No solutions
71. (∞, ∞), all real numbers are solutions.
73. x 2, x  3 75. No solutions
77. x 
5
2
Special Topics 4.6.A, page 320
1. 4/3  x  0 3. 7/6  x  11/6
5. x 11/20 or x 1/4
7. x 53/40 or x 43/40
9. x 7/2 or x 5/4 11. 1/7  x  3
13. 3
 x 1 or 1  x  3
15. x 6
or x  6
17. x  2 or 1  x  0 or x  1
19. 1.43  x  1.24 21. x .89 or x  1.56
23. x  2 or x  14/3
25. 1.13  x  1.35 or 1.35  x  1.67
27. (∞, ∞), all real numbers are solutions.
29. x  1, x  2
31. If x  3  E/5, then multiplying both sides by 5 shows
that 5x  3  E. But
5x  3  5
x  3  5(x  3)
 5x  15  (5x  4)  11. Thus,
(5x  4)  11  E.
33. (a) 2.999  x  3.001
(b) d  l  .001 where d is the desired length, and l is the
length of the manufactured rod.
Section 4.7, page 326
1. 8  2i 3. 2  10i
5. 1/2  2i 7.
2
2
3
 2i
9. 1  13i 11. 30i
ANSWERS 997
13. 21  20i 15. 4
17. i 19. i
21. i 23.
3 
13
2i
25. 
4
3
i 27.
1
4
2
1
1
4
5
1
i
29. 
4
5
1
4
4
1
i 31.
1
1
0
7
1
1
1
7
i
33.
1
7
0
1
1
1
0
i 35. 
1
1
1
7
3
0
1
4
7
1
0
i
37. 6i 39. 14i
41. 4i 43. 11i
45. (15  32
)i 47. 2/3
49. 41  i
51. (2  52
)  (5
 210)i
53.
1
6
1
6
i 5
55. x  2, y 2
57. x 3/4, y  3/2 59.
1
3
3
14
i,
1
3
3
14
i
61. 2  0i, 3  0i 63.
1
4
4
31
i,
1
4
4
31
i
65. 42  2.5i,  42  2.5i
67. 2  0i, 1  3
i, 1  3
i
69. 1  0i, 1  0i, 0  i, 0  i
71. 1
73. (a) (i) 5 (ii) 25 (iii) 8 
(iv) 8 (v) 8
(b) mod(5  12i)
75. z
w
 
 (
a
b
i
)
(
c
d
i
)
 (ac  bd)  (bc  ad)
i
 (ac  bd)  (bc  ad)i
z
 w
 
 (a  bi)
(c  di)
 (a  bi)(c  di)
 (ac  bd)  (bc  ad)i
Thus z
w
 
 z
 w
77. z
 a  b
i  a  b
i  a  bi  z
79. (a)
z 
2
z
2
a
a
 a
(b)
z 
2i
z
2
2
b
i
i
 b
81. (a) (i) (a, b)  (c, d)  (a  c, b  d)  (c  a, d  b)
 (c, d)  (a, b)
(ii) [(a, b)  (c, d)]  (e, f )  (a  c, d  d)  (e, f )
 ((a  c))  e, (b  d)  f )
 (a  (c  e), b  (d  f ))
 (a, b)  [(c, d)  (e, f )]
(iii) (a, b)  (0, 0)  (a  0, b  0)  (a, b)
(iv) (a, b)  (a, b)  (a  (a), b  (b))  (0, 0)
(a  bi)  (a  bi)
2i
(a  bi)  (a  bi)
2