
440 16. Microdemography
16.8 Parity Progression and Population Increase
How parents decide the size of their families has been the subject of much
investigation since effective birth control has made that size subject to
deliberate decision. Some may have a concept at the beginning that they
retain throughout—they are fixed on three children, say. The majority,
however, seem to make up their minds as they go along—they have one
child and then, depending on how things look, they decide whether to have
another. The following argument suggested by Norman Ryder formalizes
parental decision in terms of the probabilities of successively proceeding to
each further child.
Disregard time and consider the married couples that have children of
successive orders. Suppose that a certain fraction of women have a first
child; of these a certain fraction have a second child; of those that have two
children a certain fraction go on to a third; and so on. We might take as
the cohort a group of couples that married at the same time, or a group of
women born at the same time. We could include a symbol for the fraction
r
0
of the cohort that survives, and another for the fraction that marries,
but simplicity is served by just supposing that r
1
of the girls born at a
given moment will grow up and have a first child, of these the fraction r
2
will go on to a second child, and so on.
Then the probability that a girl child will have at least one child is r
1
,
that she will have two children is r
1
r
2
, and so on. Suppose that the ratio of
boys to girls among the births of any order is s, so the fraction 1/(1 + s)of
the births are girls. The net reproduction rate of the cohort of which the
girl in question is a member is
R
0
=
1
1+s
(r
1
+ r
1
r
2
+ r
1
r
2
r
3
+ ···). (16.8.1)
Due allowance is implicitly made for mortality, nonmarriage, illegitimacy,
and voluntary or involuntary sterility within marriage.
We can enable the notion of parity progression to serve us better by
reducing the parameters in (16.8.1) from one for each child to just two in
all. Ryder found that r
1
≈ r
2
= h,say,andthatr
3
≈ r
4
≈ r
5
≈···= k,
say. Then (16.8.1) becomes
R
0
=
1
1+s
(h + h
2
+ h
2
k + h
2
k
2
+ h
2
k
3
+ ···)
=
1
1+s
h +
h
2
1 − k
.
Table 16.6 shows values of R
0
for various combinations of h and k;the
combinations on the lower right give an increasing population.
With this result we can do experiments of various kinds. We can, in
particular, see how R
0
would be modified by lowering k,whichistheway
in which fertility change seems largely to have taken place in the United