
For
simplicity,
we
only
consider
the
irreversible
degradation
case,
i.e.,
d'
= o,
nonetheless,
the
results
obtained
are
also
valid
for
d'
> o.
Note
that
the
fixed
point
P
0
(a
= c
0
,
E = x =
0)
is
always
stable.
The
two
other
fixed
points
P
and
Q
are
positioned
at:
(p,q)
=
(c
0
c ±
[c
0
2
c•
-
4d(c
+
c'
+
cdjr)
)y,}/2
(c
+
c'+
cdjr).
Note
that
p >
q,
as
p
grows
and
q
shrinks
with
increasing
c
0
•
It
is
easy
to
show
that
Q
is
always
a
saddle
point,
and
P
either
a
sink
or
a
source.
So,
for
c
0
< csad =
[4d(c
+
c'
+
cdjr)
]Yzjc, P
0
is
the
only
fixed
point,
and
as
c
0
crosses
csad'
by
a
saddle-node
bifurcation,
P
and
Q
emerge
into
the
interior
of
s.
To
determine
the
stability
of
P,
we
evaluate
the
trace
of
the
Jacobian,
A,
at
P:
trA(x=p)
=
d-
r-
p•
(c
+
c'),
(7.5-14)
which
is
a
decreasing
function
of
C
0
•
If
at
C
0
= csad'
Eq.(7.5-
14)
is
negative,
then
Pis
stable
for
all
C
0
> csad·
This
corresponds
to
a
direct
transition
from
region
I
to
region
V
and
it
always
happens
if
d S
r.
1
~--------------------------------------,
Fig.7.5.3.
Analogously
to
the
earlier
discussion,
now
using
x-
2
as
the
Dulac
function,
and
using
the
Poincare-Bendixson
theorem
to
exclude
the
existence
of
periodic
orbits,
one
concludes
that
all
solutions
have
to
converge
to
one
of
the
fixed
points
P
0
,
P,
or
Q.
If
the
numerical
value
of
trA
of
Eq.(7.5-14)
at
c
0
= csad
is
positive,
the
fixed
point
P
is
an
unstable
node.
372