
F
i
(x) =
3
P
k=1
F
i k
(x)i
k
δA Π(x)
δA =
N
P
i=1
(F
i
, dr
i
) =
=
N
X
i=1
3
X
k=1
F
i k
(x)dx
i k
= −
N
X
i=1
3
X
k=1
∂Π(x)
∂x
i k
dx
i k
= −dΠ(x).
(19.4)
F
i
(r
1
, . . . , r
N
)
F
i
(r
1
, . . . , r
N
)
m
F
i
(r
1
, . . . , r
N
)
¤ ⇓
⇑
dΠ(x)
N
X
i=1
3
X
k=1
F
i k
(x)dx
i k
= −
N
X
i=1
3
X
k=1
∂Π(x)
∂x
i k
dx
i k
dx
i k
x
i k
¥
E
E = T + Π (19.5)
E
E = T + Π = const. (19.6)
¤
dT = δA
dT = −dΠ r
i
(t) t ∈ [t
1
, t
2
]
T
2
−T
1
= Π
1
−Π
2
E
2
= T
2
+Π
2
= T
1
+Π
1
= E
1