
15.2 The Dirac spinor 113
and there exists a direct relation between an analog combination of the Dirac matrices
and a frame of ∧M, whose dimension is 1 + 4 + 6 + 4 + 1 = 16, composed of
scalars, vectors, bivectors, pseudo-vectors, pseudo-scalars.
As evoked in the Preface, the identification of the matrices γ
μ
to the vectors e
μ
has been implicitly used by Sommerfeld [1] and Lochak [2] when they expressed
the Dirac spinor by means of the Dirac matrices, but their processes corresponded
implicitly to the abandon of the use of the Dirac spinor as it is defined above. That
was a first approach to the clear real language of the Space–Time Algebra Cl(M),
introduced independently by Hestenes in [3].
It is shown in what follows (see [4]), that the Pauli and Dirac spinors are nothing
else, when the matrices act upon them, but a decomposition of the Hamilton quater-
nion and the Clifford biquaternion, in which the number i has been replaced by the
bivector of M, e
2
∧ e
1
whose s quare in Cl(M) is equal to −1.
15.3 The Quaternion as a Real Form of the Pauli spinor
Using i =−jk one deduces from Eq. 2.12 the following form of a quaternion
q = w + kz − j(−y + kx) = u
1
− ju
2
(15.10)
A Pauli spinor ξ, associated with the biquaternion q, is represented in the form
of a column vector
ξ =
u
1
u
2
⇔ q = u
1
− ju
2
(15.11)
that is a doublet of “complex numbers” whose the “maginary number”
√
−1is
nothing else but the real bivector k = e
1
∧ e
2
= e
1
e
2
= ie
3
.
Applying (2.13) one can write, because e
k
qe
3
=−ie
k
qie
3
e
1
qe
3
=−iqk = jk(u
1
− ju
2
)k = u
2
− ju
1
⇔ σ
1
ξ
e
2
qe
3
=−jqk =−j (u
1
− ju
2
)k =−ku
2
− jku
1
⇔ σ
2
ξ
e
3
qe
3
=−kqk =−k(u
1
− ju
2
)k = u
1
− j(−u
2
) ⇔ σ
3
ξ
from which one deduce the equivalences with
σ
1
=
01
10
,σ
2
=
0 −k
k 0
,σ
3
=
10
0 −1
, k = i
e
3
(15.12)
which explain the form of the σ
k
matrices, and the reason why they obey the same
relations as orthonormal vectors of E
3
. When they act on a spinor Pauli ξ,the Hamil-
ton quaternion q, corresponding to ξ, is to be multiplied on the left by e
1
, e
2
or e
3
,
and on the right by e
3
.