126 CHAPTER 10. GEOMETRY
z<0 are “inside” and all points in space with z>0 are “outside”. (One immediately sees
how arbitrary this definition is!).
What if you were asked to locate the point (x
0
,y
0
, 0)? Based on its position, this point is
neither inside nor outside. To answer this question you would require more information,
the particle direction, ~µ =(u, v, w). You would base your decision on where the particle is
going. If the particle is on the surface, form the product ~µ · ˆn where n is the normal to the
plane. In this case ~µ · ˆn = w.If~µ · ˆn>0, it means that the particle is directed outside. If
~µ · ˆn<0, it means that the particle is directed inside. This would place the particle based
on where it is going. What if z = 0 and ~µ ·ˆn =0,orw = 0 in our case? This means that the
particle is on the plane and has a trajectory that is parallel to the plane. In this case, the
choice is arbitrary. Unless there is a special source of particles that specifically chooses this
set of conditions (and would specify the logical location of the particle), the probability that
a particle will transport and scatter into this condition is quite small. In this case, choose
either “inside” or “outside”. Eventually the particle will scatter either inside or outside the
plane and its position will be resolved at that point.
A single sphere of radius R centered at (0, 0, 0)
The equation of this surface is:
~x
2
− R
2
= x
2
+ y
2
+ z
2
−R
2
=0. (10.15)
Given a particle at position ~x
0
=(x
0
,y
0
,z
0
) and direction ~µ =(u, v, w), the quadratic
constants, A, B and C,are:
A =1
B = ~µ ·~x
0
= ux
0
+ vy
0
+ wz
0
C = ~x
2
0
− R
2
= x
2
0
+ y
2
0
+ z
2
0
− R
2
(10.16)
The sphere delineates two elemental volumes, the interior of the sphere and the exterior of
the sphere as shown in Figure 10.4.
If you were asked to locate the particle, first you would look at C = x
2
0
+ y
2
0
+ z
2
0
− R
2
.If
C<0 the particle is inside the sphere and if the C>0 the particle is outside the sphere. (In
this example, the choice of “inside” and “outside” seems a little more natural.) If C =0the
location of the particle is on the sphere and we would then look at the constant B.IfC =0
and B<0, the particle is headed inside. If C = 0 and B>0, the particle is headed outside.
If C = 0 and B = 0 the particle is on the surface and has a trajectory that is tangent to the
sphere. In this case we would appeal to the constant A. For a sphere is always has the same
value, 1. It is positive, which means the surface is curving away from the particle trajectory
and the particle is headed outside.