
Uncorrected Proof
BookID 160928 ChapID 12 Proof# 1 - 29/07/09
12.3 Green’s Function 369
We note that the contraction of a pair of operators is the anticommutator we 150
omit when we formally reorder a T product of a pair of operators to get an N 151
product. The contractions are c-numbers for the operators we are interested 152
in. 153
12.3.2 Wick’s Theorem 154
The Wick’s theorem states that T product of operators ABC ··· can be 155
expressed as the sum of all possible N products with all possible pairings. 156
By this we mean that 157
T(ABCD ···XY Z)
=N(ABCD ···XY Z)
+N(A
c
B
c
CD ···XY Z)+N(A
c
BC
c
D ···XYZ)+N(A
c
BCD
c
···XY Z)
+ ···+N(ABCD ···XY
c
Z
c
)
+N(A
c
B
c
C
a
D
a
···XYZ)+···+N(ABCD ···W
c
X
c
Y
a
Z
a
)
.
.
.
+N(A
c
B
c
C
a
D
a
···Y
b
Z
b
)+N(A
c
B
a
C
c
D
a
···Y
b
Z
b
)+ all other pairings.
(12.52)
158
In evaluating the ground state expectation value of (12.52) only the term in 159
which every operator is paired with some other operator is nonvanishing since 160
the normal products that contain unpaired operators must vanish (they anni- 161
hilate excitations that are not present in the ground state). In the second and 162
third lines on the right, in each term we bring two operators together by anti- 163
commuting, but neglecting the anticommutators, then replace the pair by its 164
contraction, and finally take the N product of the remaining n −2 operators. 165
We do this with all possible pairings so we obtain
n(n−1)
2
terms, each term 166
containing an N product of the n −2 remaining operators. In the fourth line 167
on the right, we choose two pairs in all possible ways, replace them by their 168
contractions, and leave in each term an N products of the n − 4 remaining 169
operators. We repeat the same procedure, and in the last line on the right, 170
every operator is paired with some other operator in all possible ways leaving 171
no unpaired operators. Only the completely contracted terms (last line on 172
the right of (12.52)) give finite contributions in the ground-state expectation 173
value. That is, we have 174
T(ABCD ···XY Z)
0
= T(AB)T(CD)···T(YZ)±T(AC)T(BD)···T(YZ)
± All other pairings.
(12.53)
Here,wehaveusedA
c
B
c
=T(AB) −N(AB) and noted that N(AB) =0,so 175
the ground state expectation value of A
c
B
c
= T(AB).Nowletusreturn 176
to the expansion of the Green’s function. The first term in the sum over n in 177
(12.48) is 178