
278 9 Complex Variables and Conformal Transformation in Poten tial Theory
9.6 Geophysical Problems on S-C Transformation
Two dimensional boundary value problems, which satisfy Laplace equation,
are presented in this section with considera b le details for only four problems.
These four problems can be classified in three categ ories i.e., (i) problems
where closed form solutions are available (ii) problems where closed form
solutions are not possible and numerical integration was required for its solu-
tion (ii i ) problems where closed form solutions can be obtained using elliptic
integrals and elliptic functions.
9.6.1 Problem 1 Conformal Transformation for a Substratum
of Finite Thickness
In this problem two plane parallel boundaries are assumed. The region in
between those boundaries constitutes the interior of a polygon with one angle
only as we move from one point of the polygon to the other. This region is
assumed to have a finite resistivity. Resistivities outside are infinitely high. In
geophysical model simulation resistivity of the crystalline basement is assumed
to be infinitely high in comparison to sediments of finite resistivity and thick-
ness. Above the air earth boundary, resistivity of the air is infinitely high
(Roy 1967).
Figure 9.8 a,b show the geometry of the problem in the Z plane and its
transformation on the real axis of the w plane. Here the thickness and resistiv-
ity of the top layer is ‘h’ and ‘ρ’ resp ectively. The point source of current I is
located at (0, h). For every problems we have to fix the origin on the z-plane.
Here the origin is fixed at a depth ‘h’ from the surface and on top of the
basement. Now the boundary conditions are dv/ dy = 0 at y = 0 and h. The
Schwarz Christoffel method of conformal transformation, for transforming the
geometry of the z-plane on to the real axis of the w-plane are bounded by the
following equation
dz
dw
=A(w− a)
−α/π
(w − b )
−β/π
(w − c)
−γ/π
(w −d)
−δ/π
(9.73)
where ‘a’, ‘b’, ‘c’, ‘d’ are the values of w at the corners of the polygon and ‘A’
is a constant as discussed. As we move from A to C, we cross the corner BB
′
only as there are no other corners. Hence the (9.73) reduces to the form
dz
dw
=A(w− a)
−α/π
. (9.74)
NowaswemoveacrossBB
′
, our movement has turned through an angle
of 180
0
or π because we started moving in the opposite direction. Therefore
α = π. Since we move towards the polygon (shown by the dotted lines) the
sign of the argument ‘α’ will be + or positive. Therefore (9.74) reduce, to the
form