
Exercises 133
9.4.
?
Show that the one-stage method in Section 9.3 is a special case of
the two-stage process (9.9) by choosing appropriate values of a, b
1
,
and b
2
. Hence show that we must have b
1
= 1 so that the method in
Section 9.3 has order one.
9.5.
??
Prove, from first principles, that the RK method
k
1
= f(t
n
, x
n
),
k
2
= f(t
n
+ h, x
n
+ hk
1
),
x
n+1
= x
n
+
1
2
h(k
1
+ k
2
),
is a consistent method (of order at least p = 1) for solving the IVP
x
0
(t) = f (t, x(t)), with x(0) = η.
9.6.
??
Prove, from first principles, that the RK method
k
1
= f(t
n
, x
n
),
k
2
= f(t
n
+
3
2
h, x
n
+
3
2
hk
1
),
x
n+1
= x
n
+
1
3
h(2k
1
+ k
2
),
is consistent of at least second order for solving the initial value
problem x
0
(t) = f (t, x(t)), t > 0 with x(0) = η.
9.7.
?
Consider the solution of the IVP x
0
(t) = (1 −2t)x(t) with x(0) = 1.
Verify the values (to six decimal places) given below for x
1
with
h = 0.1 and the metho ds shown. The digits underlined coincide
with those in the exact solution x(h) = exp[
1
4
− (
1
2
− h)
2
].
Improved Modified Heun Kutta Fourth
Euler Euler third order order
1.094 000 1.094 500 1.094 179 1.094 187 1.094 174
9.8.
??
Apply the general second-order, two-stage RK method (see Ta-
ble 9.5) to the ODE x
0
(t) = t
2
. Compare x
n+1
with the Taylor
expansion of x(t
n+1
) and comment on the order of the LTE.
9.9.
??
Apply the general second-order, two-stage RK method (see Ta-
ble 9.5) to the ODE x
0
(t) = λx(t). Compare x
n+1
with the Tay-
lor expansion of x(t
n+1
) and show that the difference is O(h
3
) if
x
n
= x(t
n
). We conclude that the order of the metho d cannot ex-
ceed two while the calculations in Section 9.4 show that the order is
at least 2; the order must therefore be exactly 2.