
832 Chapter 26. Quantum Mechanics of Interacting Magnetic Moments
In two and three dimensions, there is only one point of general agreement. At
half filling, where the number of electrons precisely equals the number of lattice
sites,
and for large enough U, the ground state is antiferromagnetic. Some reasons
for this conclusion are explored in Problem 9. This conclusion has considerable
physical importance, because it provides the simplest way to see how solids like
CuO (Section 23.6.3) that should be metals according to band theory actually turn
out to be antiferromagnetic insulators, called Mott-Hubbard or Mort insulators.
Even this statement needs to be qualified, because charge transfer between oxygen
and copper as discussed in Section 23.6.3 is not included in the Hubbard model,
which is hard enough to solve without it. Away from half filling, the problem is
not completely solved. Figure 26.12 displays five characteristic phase diagrams
describing the ground state of the Hubbard model as a function of U/t and of A
or chemical potential /i; A gives the fraction of electrons per site in excess of half
filling, so there is one electron per site when A = 0, and two electrons per site when
A = 1. The chemical potential ß enters the model by adding (//
—
U/2) J2i
n
ito
Eq. (26.139).
The fact that the properties of the two-dimensional Hubbard model are not
yet known with certainty is unsatisfactory because the Hubbard model is widely
viewed as the simplest context in which to try to obtain exact results for many inter-
acting electrons; this model has been investigated with a ferocious intensity since
the discovery of high-temperature superconductors. There is no better illustration
of the difficulties involved in progressing systematically beyond the one-electron
pictures of solids.
Problems
1.
Wave functions with cusps: Show that the energy of
\cj)\
in Figure 26.2
can certainly be lowered by smoothing out the cusp. One way to perform
the demonstration is to flatten out the wave function as shown in the figure
throughout some small volume v and then estimate the effect on kinetic and
potential energies.
2.
Ferromagnetic ground state: Consider the Hamiltonian (26.21) with all J
positive, and take S$ to describe spin 1/2 particles.
(a) Show with the aid of the identity in Eq. (26.19) that the state where all spins
are eigenvalues of S
z
with eigenvalue 1/2 is an eigenfunction of the Hamilto-
nian.
(b) Show that the largest value that (^\S^
•
S$,
|\I/)
can assume for R ^ R' in any
wave function \I> is less than or equal to the largest eigenvalue of S^
■
S^,. By
expanding out the square of S^ + S^,, show that the largest eigenvalue of this
operator is 1/4.
(c) Therefore show that the ferromagnetic state provides the ground state of the
Heisenberg Hamiltonian.