
268 Part 1 Semiconductor Devices and Basic Applications
PROBLEMS
Section 4.1 The MOSFET Amplifier
4.1 An NMOS transistor has parameters
V
TN
= 0.4
V,
k
n
= 100 μ
A/V
2
, and
λ = 0.02
V
−1
. (a) (i) Determine the width-to-length ratio
W/L
such that
g
m
= 0.5
mA/V at
I
DQ
= 0.5
mA when biased in the saturation region.
(ii) Calculate the required value of
V
GSQ
. (b) Repeat part (a) for
I
DQ
= 0.15
mA.
4.2 A PMOS transistor has parameters
V
TP
=−0.6
V,
k
p
= 40 μ
A/V
2
, and
λ = 0.015
V
−1
. (a) (i) Determine the width-to-length ratio
(W/L)
such that
g
m
= 1.2
mA/V at
I
DQ
= 0.15
mA. (ii) What is the required value of
V
SGQ
? (b) Repeat part (a) for
I
DQ
= 0.50
mA.
4.3 An NMOS transistor is biased in the saturation region at a constant
V
GS
.
The drain current is
I
D
= 3
mA at
V
DS
= 5
V and
I
D
= 3.4
mA at
V
DS
=
10 V. Determine
λ
and r
o
.
4.4 The minimum value of small-signal resistance of a PMOS transistor is to
be
r
o
= 100
k. If
λ = 0.012 V
−1
, calculate the maximum allowed value
of I
D
.
4.5 An n-channel MOSFET is biased in the saturation region at a constant
V
GS
.
(a) The drain current is
I
D
= 0.250
mA at
V
DS
= 1.5
V and
I
D
= 0.258
mA
at
V
DS
= 3.3
V. Determine the value of
λ
and
r
o
. (b) Using the results of
part (a), determine
I
D
at
V
DS
= 5
V.
4.6 The value of
λ
for a MOSFET is
0.02 V
−1
. (a) What is the value of r
o
at
(i)
I
D
= 50 μA
and at (ii)
I
D
= 500 μA
? (b) If
V
DS
increases by 1 V, what
is the percentage increase in I
D
for the conditions given in part (a)?
4.7 A MOSFET with
λ = 0.01 V
−1
is biased in the saturation region at
I
D
=
0.5 mA. If
V
GS
and
V
DS
remain constant, what are the new values of I
D
and
r
o
if the channel length L is doubled?
4.8 The parameters of the circuit in Figure 4.1 are
V
DD
= 3.3
V and
R
D
= 5
k
. The transistor parameters are
k
n
= 100 μ
A/V
2
,
W/L = 40
,
V
TN
= 0.4 V, and λ = 0.025
V
−1
. (a) Find
I
DQ
and
V
GSQ
such that
V
DSQ
= 1.5
V. (b) Determine the small-signal voltage gain.
4.9 The circuit shown in Figure 4.1 has parameters
V
DD
= 2.5
V and
R
D
= 10
k
. The transistor is biased at
I
DQ
= 0.12
mA. The transistor pa-
rameters are
V
TN
= 0.3
V,
k
n
= 100 μ
A/V
2
, and
λ = 0
. (a) Design the
W/L
ratio of the transistor such that the small-signal voltage gain is
A
v
=−3.8
. (b) Repeat part (a) for
A
v
=−5.0
.
4.10 For the circuit shown in Figure 4.1, the transistor parameters are
V
TN
= 0.6
V,
k
n
= 80 μ
A/V
2
, and
λ = 0.015
V
−1
. Let
V
DD
= 5
V. (a) De-
sign the transistor width-to-length ratio
W/L
and the resistance
R
D
such that
I
DQ
= 0.5
mA,
V
GSQ
= 1.2
V, and
V
DSQ
= 3
V. (b) Determine
g
m
and
r
o
.
(c) Determine the small-signal voltage gain
A
v
= v
o
/v
i
.
*4.11 In our analyses, we assumed the small-signal condition given by Equa-
tion (4.4). Now consider Equation (4.3(b)) and let
v
gs
= V
gs
sin ωt
. Show
that the ratio of the signal at frequency
2ω
to the signal at frequency
ω
is
given by
V
gs
/[4(V
GS
− V
TN
)]
. This ratio, expressed in a percentage, is
called the second-harmonic distortion. [Hint: Use the trigonometric iden-
tity
sin
2
θ =
1
2
−
1
2
cos 2θ
.]
4.12 Using the results of Problem 4.11, find the peak amplitude V
gs
that produces
a second-harmonic distortion of 1 percent if
V
GS
= 3
V and
V
TN
= 1
V.
nea80644_ch04_205-284.qxd 06/12/2009 08:00 PM Page 268 F506 Tempwork:Dont' Del Rakesh:June:Rakesh 06-12-09:MHDQ134-04: