
290 Chapter 8 Spherically symmetric spacetimes
increasingly complicated fine-grained structure of the distribution function due to phase
mixing. For determining the global behavior of a collisionless system, the mean-field
particle-simulation scheme is quite adequate. However, to obtain a detailed description of
the phase space distribution, especially when there is counter-streaming and phase mixing,
the direct phase space method is necessary.
Adopt the form for the line element given in equation (8.41). Again assume for simplicity
that the gas consists of a single species of mass m. As coordinates in phase space, choose
the radial velocity u
r
, the specific angular momentum j given by
j ≡
)
u
2
θ
+
u
2
φ
sin
2
θ
, (8.82)
and the angle
ψ ≡ tan
−1
u
ˆ
θ
u
ˆ
φ
= tan
−1
u
θ
sin θ
u
φ
, (8.83)
measuring the orientation of the transverse velocity. Here the carets denote orthonormal
components. In spherical symmetry, f cannot depend on ψ,and j is a conserved quantity,
so that the Boltzmann equation (5.217) reduces to
∂ f
∂t
+
dr
dt
∂ f
∂r
+
du
r
dt
∂ f
∂u
r
= 0 (8.84)
since ∂ f /∂ψ = 0anddj/dt = 0. Here we have taken f = f (t, x
j
, u
j
) ≡
dN/(d
3
V
x
d
3
V
u
), where d
3
V
u
= d
3
V
p
/m
3
and where d
3
V
p
is given by equation (5.213).
Exercise 8.12 Show that for a spherical metric given by equation (8.41)(−g)
1/2
=
A
3
αr
2
sin θ and
d
3
V
u
=
du
r
du
θ
du
φ
A
3
r
2
αu
0
sin θ
=
π
A
3
r
2
αu
0
dj
2
du
r
, (8.85)
where the integral over ψ has been carried out in the last expression.
In spherical symmetry, we can thus write f = f (t, r, u
r
, j). The coefficients dr/dt and
du
r
/dt in equation (8.84) are given by geodesic equations (8.42) and (8.43). The field
equations are unchanged from those described in the previous section. The matter source
terms are derived from f as in equations (5.207)–(5.210), using equation (5.213). For
example, the quantity ρ(t, r ) can be computed from
ρ = m
(αu
0
)
2
fd
3
V
u
=
πm
A
3
r
2
∞
0
dj
2
∞
−∞
du
r
f
1 +
u
2
r
A
2
+
j
2
A
2
r
2
1/2
. (8.86)
Note that one must be careful when evaluating the source terms at r = 0, where f = 0
only for j = 0. The coordinate singularity at r = 0 in these quadratures is eliminated by
recasting the d
3
V
u
in terms of velocity components in an orthonormal frame: d
3
V
u
=
(du
ˆ
x
du
ˆ
y
du
ˆ
z
)/u
ˆ
0
. The point r = 0 is the center of symmetry, in which case the distribution