
5.5 Applications 161
system with two zeros. In this situation the controlled system will always exhibit
complex closed-loop poles (as shown in fig. 5.23, and thus, the output will
oscillate.
5.5 Applications
In this section we will deal with the use of rltool for adjusting a PID controller
through an illustrative example. Let’s consider a plant represented by the transfer
function:
(5.4)
For which, the following restrictions are established: a) Maximum overshoot <
5%, b) Settling time< 2 seconds, and c) null steady-state error for step inputs.
Factorizing the denominator of expression (5.2), it can be noticed that system is of
type 0, and thus, it presents a steady-error against step input. As commented, a
PID controller adds an integrator to the system, and thus, it increases the type of
the system, which would solve the requirement c).
(5.5)
A PID controller also adds two zeroes to the open-loop system whose location will
affect, primarily, the transient response of the controlled system. Thus, in order to
fulfill the proposed constrictions, we can proceed by placing two zeroes within the
root locus provided by rltool, adjusting their position until the constrictions are
met.
Fig. 5.24 shows the root locus of the original system, where the correspondent
constraints have been considered. The yellow area of the s-plane indicates the
incorrect position of the poles in close-loop for achieving the restrictions of
maximum overshoot and established settling time. To fulfill such restrictions we
should be able to move the poles of the system out of the yellow area, which is
impossible for the current system.
When adding an integrator, i.e. a pole at s=0, the root locus changes notably, as
shown in fig. 5.25. Now there is a segment that starts at the pole at s=-1 and runs
tending to -∞ over the real axis. Thus there will be a value for the compensator K
that moves out this pole from the yellow area, but not the others. Moreover, the
root locus is bended to the right, making the system unstable for certain values of
the compensator. Concretely this system is unstable for K ∈[0.25,∞).
2
6
()
231
Gs
ss
=
++
6
()
(2 1)( 1)
Gs
ss
=
++