
13.6 A Generalization of Aromaticity: Hückel’s 4
n
ⴙ 2 Rule 593
A remarkable amount of effort was expended on the synthesis of the cyclodec-
apentaenes before they were successfully made.The magnitude of this effort should
make us suspicious; aromatic compounds are everywhere and extraordinarily easy to
make. Moreover, the known cyclodecapentaenes are not only not especially stable,
they are instead strikingly unstable. So, we have some explaining to do.We have been
relying on a theory that predicts special stabilization conferred by the aromatic 4n 2
number of π electrons, and the cyclodecapentaenes are members of the 4n 2 club.
If we cannot explain why these molecules are unstable, Hückel’s rule must be aban-
doned. It turns out to be not too difficult to resolve the problem. Aromatic stability
is not some magical force. It is just one kind of stabilizing effect, which in the face
of stronger destabilizing effects will not prevail.Put simply, the planar cyclodecapen-
taenes are destabilized by an amount greater than aromaticity can overcome. What
might those destabilizing effects be? Look first at the molecule on the right in
Figure 13.35, the trans,cis,trans,cis,cis isomer. For the molecule to be flat, the two
hydrogens inside the ring must occupy the same space.This crowding induces extraor-
dinary strain that is greater than any resonance stabilization. The molecule cannot
be flat. Aromaticity cannot compensate for this strong destabilizing effect.
The trans,cis,cis,cis,cis isomer, the middle molecule in Figure 13.35, has some
of the same problems, although here only one hydrogen is inside the ring. In this
molecule,however, there is severe angle strain,and the planar form, required for aro-
maticity, is badly destabilized.
The all-cis isomer, the molecule on the left in Figure 13.35, has even more angle
strain, and it too can be planar, and therefore aromatic, only at a prohibitively high
energy cost. The benefits of delocalization are overwhelmed by the angle strain.
A good set of models will show this strain easily. Construct the planar, all-cis
cyclodecapentaene and the strain will be apparent. If you are lucky, the plastic will
mimic the molecule and the model will snap into a pretzel shape, which approxi-
mates the energy minimum form of the molecule.These molecules are best described
as strained polyenes. They fail the test of planarity for aromatic molecules because
the planar structures are much more strained than the nonplanar forms. In this case,
strain trumps aromaticity.
PROBLEM 13.14 The all-cis cyclodecapentaene forms a new, cross-ring bond (see
below). As the molecule warms up, a bicyclo[4.4.0]decatetraene is formed. Write
an arrow formalism for this reaction.
cis,cis,cis,cis,cis-
Cyclodecapentaene
Bicyclo[4.4.0]deca-
2,4,7,9-tetraene
Δ
So we haven’t really judged the limits of the theory of aromaticity by using the
cyclodecapentaenes. We might be able to if the offending strain could somehow be
removed. On paper, this transfomation is simple. For example, we might just erase
the two inside hydrogens in one of the molecules (Fig. 13.36). Unfortunately, this
erasure doesn’t give a real molecule because this structure has two trivalent carbons
at the positions marked with dots in Figure 13.36.
trans,cis,trans,cis,cis-
Cyclodecapentaene
(strain caused by the
inside red hydrogens)
H
H
magic
hydrogen
eraser
(much less strain! But…
what is going on at the
red-dot positions?)
FIGURE 13.36 The strain caused
by two inside hydrogens in one
cyclodecapentaene can be eliminated
by removing the offending
hydrogens.