
132 Formal Methods of Electrostatics
of the maximum (or minimum) would be penetrated by a non-vanishing electrical
flux. This is only possible if there are volume charges present, which would require
. Therefore, the assumption of a maximum or minimum inside of this area
would lead to a contradiction. Then, if on the boundary, it can not be larger
inside, but it can also not be smaller than zero inside and consequently
everywhere in the region. In other words: If in a region , then the
function may have its maximum or minimum values only on the boundary of that
region. Uniqueness of the solution of Dirichlet’s boundary value problem is an
immediate consequence of this statement.
3.4.4 Models
The equation has a frequent occurrence in physical science and it
describes a vast number of problems. This enables one to frequently map physical
problems onto a corresponding electrostatic problem. For example, the two-
dimensional Laplace’s equation
also describes the displacement of a membrane suspended on a frame which is
considered to be small. The boundary (frame) defines and inside .
Such a membrane can be considered a model for electrostatic problems.
3.4.5 Dirac’s Delta Function (δ-Function)
The -function is particularly useful in the following, which is why we will
introduce it here. It shall be noted that our exposition here does not substitute a
rigorous mathematical introduction.
A rough, illustrative way to describe the character of the -function is to note
that it vanishes everywhere except for one particular point of its argument (namely
0), where it takes an infinite value, exactly such that its integral equals 1.
(3.49)
(3.50)
The -function is not a function in the usual sense. It belongs to a more general
category of functions, which sometimes are called improper functions, generalized
functions, or distributions. Another possibility is to imagine the -function as the
limit of a series of functions. It can be constructed in various ways, for example,
1. The limit of a series of rectangular functions as illustrated in Fig. 3.7.
Thus
∇
2
ϕ 0≠
ϕ 0=
ϕ 0=
∇
2
ϕ 0=
ϕ
∇
2
ϕ 0=
x
2
2
∂
∂
y
2
2
∂
∂
+
ϕ 0=
ϕ∇
2
ϕ 0=
δ
δ
δ xx'–()
0 forxx'≠
∞ for xx'=
=
δ xx'–()xd
∞–
+∞
∫
1=
δ
δ