428 Time Dependent Problems II (Electromagnetic Waves)
This is by no means the most general case. This is obtained if
,
(7.112)
where and are vectors for which the dispersion relation has to hold, i.e.,
.
(7.113)
If the two vectors and are parallel, then the appropriate choice of coordinate
system allows to arrive at the same expression as stated in (7.111), and thus one
obtains a homogeneous wave in the just defined sense. The planes of constant
phase are perpendicular to . The planes of constant amplitude are perpendicular
to . If the two vectors point in different directions, then the result is an
inhomogeneous wave. In order to be able to provide a simple example, let
in (7.113). This forces and to be perpendicular. One may assume, for
example, that
,
(7.114)
which results in the wave
.
(7.115)
For the relation between b and a we have
.
(7.116)
Inhomogeneous waves are not transverse, as (7.90) clearly shows. Moreover, they
are not plane waves in the sense of our definition because the amplitude is not
constant in the planes where the phase is constant. Nevertheless, inhomogeneous
waves are important. Oftentimes, they are necessary to satisfy boundary
conditions, e.g., for reflection problems. We will come back to such cases.
The magnetic field that belongs to the wave described by (7.111) results from
(7.90). B is perpendicular to E. However, there is a phase difference between B and
E because k is a complex vector. There was no phase difference in the ideal
insulator ( ). If the electric field is
,
then the magnetic field becomes
Notice that B has only a y-component
.
If is real valued, then the electric field expressed in real value notation is
(7.117)
and the magnetic field is
k b ia–=
ab
µεω
2
µκiω– b
2
i2ab• a
2
––()–0=
ab
b
a
κ 0=
a
k b 0 ia–,,〈〉=
EE
0
i ωtbx–()[]exp az–[]exp=
b
2
– a
2
µεω
2
++ 0=
κ 0=
E
0
E
x0
00,,〈〉=
B
00β iα–,,〈〉
ω
--------------------------------
E
x0
00,,〈〉i ωt βz–()[]exp αz–[]exp×=
0β iα–()E
x0
0,,〈〉
i ωt βz–()[]exp αz–[]exp
ω
----------------------------------------------------------------
.=
B
y
β iα–()E
x0
ω
-----------------------------
i ωt βz–()[]exp αz–[]exp=
E
x0
E
x
E
x0
ωt βz–()cos αz–[]exp=