
7.10 Circular Wave Guide 493
This describes an electric field which is purely radial and a magnetic field that is
purely azimuthal. Fig. 7.38 illustrates this. Since
(7.426)
one finds
,
(7.427)
i.e., the wave behaves in this respect like a plane wave. There is no difficulty in
satisfying the boundary conditions, because there are neither components of E
parallel to the boundary, nor perpendicular components of H. must decrease as
so that E remains source-free, while needs to decrease as so that H
remains irrotational.
For the sake of completeness, it shall be noted that the just derived TEM wave
can also be obtained from
.
For
,
is the most general solution of (7.418). If we take for , then it has to be
because of (7.363), which in conjunction with provides the
fields given in (7.425). If we take for , then it has to be because
of (7.355), which in conjunction with yields as given above. With
the appropriate choice of , this provides the fields (7.425).
Wave types are also called modes. The just found TEM mode of the coaxial
cable is very similar to the TEM wave between two parallel plates. The two
converge for . We could think of Fig. 7.29 as being a piece of an annular
region with a very large radius.
According to (7.426), the TEM wave propagates with the speed of light for
that particular dielectric:
.
(7.428)
The just found wave is also used in transmission theory, where the telegrapher's
equation is used instead of the wave equation. To better illustrate the relation, we
shall now derive the telegrapher's equation and briefly discuss it.
7.10.5 Telegrapher's Equation
To derive the telegrapher's equation, one imagines the transmission line as being a
continuous analog of a network circuit, where a transmission line is nothing more
than a multiply connected wave guide of arbitrary cross section. The coaxial cable
N εµω
2
k
z
2
–0==
H
ϕ
E
r
Z
-----=
E
r
1 r⁄ H
ϕ
1 r⁄
Π
mz
D
1
D
2
ϕ+()i ωtk
z
z–()[]exp=
m 0=
Π
z
C
1
C
2
r
r
0
----ln+
D
1
D
2
ϕ+()i ωtk
z
z–()[]exp=
Π
z
Π
ez
D
2
0= D
1
1=
Π
z
Π
mz
C
2
0=
C
1
1= Π
mz
D
2
r
a
r
i
r
a
«–
v
ph
ω
k
z
----
1
εµ
---------- c== =