
214 Chapter 8. Nearly
Free
and Tightly Bound Electrons
Example: Brillouin Zone Boundary Intersection for Square Lattice in
Two
Di-
mensions.
Suppose the lattice has two conduction electrons
per lattice site. As discussed after Eq. (7.50), the num-
ber of k states in a Brillouin zone equals the number
of lattice points, and because each k state can accom-
modate precisely two electrons, the volume that the
electrons occupy in k space must equal the volume of
the Brillouin zone. However, for a weak potential, the
shape of the energy surface must be very close to the
shape of the energy surface for free electrons—that is,
a sphere. For a square lattice with lattice spacing a, the reciprocal lattice is also
square, with lattice spacing 2π/α, and the volume of the Brillouin zone is 4π
2
/α
2
.
The Fermi sphere for free electrons must have this same volume, which means
trkf-
= 4π
2
/α
2
=>
kp = 2π/
ν
/
πο =
1.128π/α.
Because at its point of closest ap-
proach the Brillouin zone boundary is at a distance n/a from the origin of K space,
the Fermi surface juts slightly out of the first Brillouin zone.
8.3.1 Nearly Free Electron Fermi Surfaces
The consequences of a Fermi surface intersecting a Brillouin zone boundary are
depicted in Figure 8.4. This Fermi surface completely contains the first Brillouin
zone,
and it extends into the second and third zones. Band energies are continu-
ous in the reduced zone scheme, and the Fermi surface should be continuous and
differentiable in the reduced zone scheme as well, as shown in Problem 2. The
Fermi surface must therefore be modified slightly from its free-electron form near
the Brillouin zone boundaries, as shown in Figure 8.4(A). Important as this fact
may be for electron dynamics, it is nearly invisible in its effect on the geometry
of the Fermi surface, so distortions near the zone edge will not be shown in sub-
sequent figures. Figures
8.4(B)
and
8.4(C)
show how to displace portions of the
free-electron Fermi surface to make them continuous in the reduced zone scheme.
In the case of the third Brillouin zone, some trial and error is needed to find ways
to displace the disjoint regions through reciprocal lattice vectors so that the energy
surface becomes continuous. Figure
8.4(D)
illustrates the Harrison construction,
which provides a systematic procedure by which to obtain pictures of the Fermi
surface in the reduced zone scheme. The Harrison construction involves nothing
but unions of intersections of spheres with the first Brillouin zone, and therefore it
provides a convenient algorithm by which to generate pictures of Fermi surfaces in
three dimensions.
Figure 8.5 illustrates the application of this construction to the Fermi sphere
of an fee crystal with three electrons per site. The left side of the figure shows
portions of the Fermi sphere lying within the second and third Brillouin zones,
while the right hand side of the figure shows how precisely the same sections of