
492
Chapter 17.
Transport
Phenomena and Fermi Liquid Theory
As a consequence of Liouville's theorem, one can choose to integrate either
with respect to k
t
and r
t
or with respect to k
t
i and 7y; the integration measures
are the same. Therefore, if it were not for the troublesome term
df(t')/d^,
the
integrand of Eq. (17.51) would be quite symmetrical. The condition for Onsager
reciprocity is therefore that it not matter whether df/d/i is evaluated at k, r or at
~kt',
r
t
'-
This requirement permits Onsager's symmetries to survive large magnetic fields,
because although magnetic fields make
k
t
r
rotate, they do it in such a way that the
energy of the particle does not change, and
k =
k,,=>f(
t
)
=
f(
t
')-
(
17
-
52
)
By contrast, electric fields conserve £
—
eV rather than £, so electric fields are not
allowed to be too large. However, one only has to worry about times on the order
of the relaxation time r
£
, or electron motions through a mean free path, because
otherwise the exponential becomes small. So the condition for the symmetries
(17.50) to hold is that all externally imposed electrical and thermal potentials must
vary negligibly on the scale of
the
electron mean free path. Under these conditions,
the integrand of
Eq.
(17.51) has the following symmetries. Send
f
' (17.53a)
If
one
starts out with some initial condition k, r, then run-
ning it forwards in time by t
—
;' is the same as reversing (17.53b)
the sign of B and k, and running it backward in time by
amount t
—
t'.
Using the symmetries Eq. (17.53) and switching to an integral over
k
t
>,
r
t
i in
Eq. (17.51) results in the Onsager symmetry (17.50).
17.4 Thermoelectric Phenomena
Boltzmann's equation in the form of (17.36) provides everything needed to explore
the response of solids to electrical, magnetic, and thermal fields. In what follows,
all electrons are assumed to belong to some particular band n, and therefore the
band index n will not be written explicitly. When more than one band crosses
the Fermi surface, contributions of the several bands would need to be summed
together.
17.4.1 Electrical Current
Consider first a solid immersed only in a uniform electrical field. The electrical
current per volume j is
t^>
B^
h-
r,'~
t'- t'
-B
y-k.
>r-
t
>
7*
ç This integral will find the current contributed by
7 „ I \yft] 75-, p -, electrons in the nth band, and accordingly the in- /IT C^\
J
-
v
- c J ^ »,
S7k
.
tegrai
is over the first Brillouin zone, not all of k