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So, to summarize, if a population is in Hardy–Weinberg
equilibrium with allele frequencies of p and q, then the prob-
ability that an individual will have each of the three possible
genotypes is p
2
+ 2pq + q
2
. You may recognize this as the bino-
mial expansion:
(p + q)
2
= p
2
+ 2pq + q
2
Finally, we may use these probabilities to predict the dis-
tribution of genotypes in the population, again assuming that
the population is in Hardy–Weinberg equilibrium. If the prob-
ability that any individual is a heterozygote is 2pq, then we
would expect the proportion of heterozygous individuals in the
population to be 2pq; similarly, the frequency of BB and bb ho-
mozygotes would be expected to be p
2
and q
2
.
Let us return to our example. Remember that 16% of the
cats are white. If white is a recessive trait, then this means that
such individuals must have the genotype bb. If the frequency of
this genotype is q
2
= 0.16 (the frequency of white cats), then q
(the frequency of the b allele) = 0.4. Because p + q = 1, therefore,
p, the frequency of allele B, would be 1.0 – 0.4 = 0.6 (remember,
the frequencies must add up to 1). We can now easily calculate
the expected genotype frequencies: homozygous dominant
BB cats would make up the p
2
group, and the value of p
2
= (0.6)
2
= 0.36, or 36 homozygous dominant BB individuals in a popula-
tion of 100 cats. The heterozygous cats have the Bb genotype
and would have the frequency corresponding to 2pq, or (2 * 0.6
*
0.4) = 0.48, or 48 heterozygous Bb individuals.
Using the Hardy–Weinberg equation to predict
frequencies in subsequent generations
The Hardy–Weinberg equation is another way of expressing the
Punnett square described in chapter 12, with two alleles assigned
frequencies, p and q. Figure 20.3 allows you to trace genetic re-
assortment during sexual reproduction and see how it affects the
frequencies of the B and b alleles during the next generation.
In constructing this diagram, we have assumed that the
union of sperm and egg in these cats is random, so that all com-
binations of b and B alleles occur. The alleles are therefore
mixed randomly and are represented in the next generation in
proportion to their original occurrence. Each individual egg or
sperm in each generation has a 0.6 chance of receiving a B allele
( p = 0.6) and a 0.4 chance of receiving a b allele (q = 0.4).
In the next generation, therefore, the chance of combining
two B alleles is p
2
, or 0.36 (that is, 0.6 * 0.6), and approximately
36% of the individuals in the population will continue to have
the BB genotype. The frequency of bb individuals is q
2
(0.4 * 0.4)
and so will continue to be about 16%, and the frequency of Bb
individuals will be 2pq (2 * 0.6 * 0.4), or on average, 48%.
Phenotypically, if the population size remains at 100 cats,
we would still see approximately 84 black individuals (with either
BB or Bb genotypes) and 16 white individuals (with the bb geno-
type). Allele, genotype, and phenotype frequencies have remained
unchanged from one generation to the next, despite the reshuf-
fling of genes that occurs during meiosis and sexual reproduc-
tion. Dominance and recessiveness of alleles can therefore be
seen only to affect how an allele is expressed in an individual and
not how allele frequencies will change through time.
Hardy–Weinberg predictions can be
applied to data to nd evidence
of evolutionary processes
The lesson from the example of black and white cats is that if
all five of the assumptions listed earlier hold true, the allele and
genotype frequencies will not change from one generation to
the next. But in reality, most populations in nature will not fit
all five assumptions. The primary utility of this method is to
determine whether some evolutionary process or processes are
operating in a population and, if so, to suggest hypotheses about
what they may be.
Suppose, for example, that the observed frequencies of
the BB, bb, and Bb genotypes in a different population of cats
were 0.6, 0.2, and 0.2, respectively. We can calculate the allele
frequencies for B as follows: 60% (0.6) of the cats have two B
alleles, 20% have one, and 20% have none. This means that the
average number of B alleles per cat is 1.4 [(0.6 × 2) + (0.2 × 1) +
(0.2 × 0) = 1.4
]. Because each cat has two alleles for this gene, the
frequency is 1.4/2.0 = 0.7. Similarly, you should be able to cal-
culate that the frequency of the b allele = 0.3.
If the population were in Hardy–Weinberg equilibrium,
then, according to the equation earlier in this section, the fre-
quency of the BB genotype would be 0.7
2
= 0.49, lower than it
really is. Similarly, you can calculate that there are fewer
heterozygotes and more bb homozygotes than expected; then
clearly, the population is not in Hardy–Weinberg equilibrium.
What could cause such an excess of homozygotes and
deficit of heterozygotes? A number of possibilities exist, includ-
ing (1) natural selection favoring homozygotes over heterozy-
gotes, (2) individuals choosing to mate with genetically similar
individuals (because BB * BB and bb * bb matings always produce
homozygous offspring, but only half of Bb * Bb produce hetero-
zygous offspring, such mating patterns would lead to an excess
of homozygotes), or (3) an influx of homozygous individuals
from outside populations (or conversely, emigration of hetero-
zygotes to other populations). By detecting a lack of Hardy–
Weinberg equilibrium, we can generate potential hypotheses
that we can then investigate directly.
The operation of evolutionary processes can be detected
in a second way. As discussed previously, if all of the Hardy–
Weinberg assumptions are met, then allele frequencies will stay
the same from one generation to the next. Changes in allele
frequencies between generations would indicate that one of the
assumptions is not met.
Suppose, for example, that the frequency of b was 0.53 in
one generation and 0.61 in the next. Again, there are a number
of possible explanations: For example, (1) selection favoring in-
dividuals with b over B, (2) immigration of b into the population
or emigration of B out of the population, or (3) high rates of
mutation that more commonly occur from B to b than vice ver-
sa. Another possibility is that the population is a small one, and
that the change represents the random fluctuations that result
because, simply by chance, some individuals pass on more of
their genes than others. We will discuss how each of these pro-
cesses is studied in the rest of the chapter.
400
part
IV
Evolution
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