
applicable to models that require numerical solution as well, is to set all derivatives (accu-
mulation terms) to zero. The differential equations then become algebraic and are solved
as such. Do not confuse steady state with equilibrium. As long as a net reaction is occur-
ring in a compartment, it may still be balanced by flux terms. For example, an organism
could be ingesting benzene on a daily basis and biotransforming it to phenol for excretion.
As long as the rate of ingestion equals the rate of reaction, there will be no accumulation
of benzene, and the system will be at steady state.
Equilibrium formally refers to a situation when the chemical potential of reactants
and products are equal for all reactions. In practical terms, equilibrium means that instead
of using the rate laws and mass transfer flux equations to describe the reactions, one sub-
stitutes equi librium relationships such as equation (5.9) for reaction equilibrium or equa-
tion (18.1) for mass transfer equilibrium. Just as steady state does not mean ‘‘no reaction,’’
equilibrium does not mean ‘‘no reaction.’’ For example, chloroform in respired air may be
assumed to be in mass transfer equilibrium with its concentration in blood plasma, yet a
continuous transfer of the solute will continue as long as the air is changed continually.
In the next several sections some simple compartment models are developed, both to
illustrate the modeling process and because they have several important features that are
used to describe the fate and transport of toxins in biological systems.
18.7.1 Dynamic Model and the Half-Life
The most basic model, of course, is the one-compartment model, in which the compart-
ment represents a whole organism. As a hypothetical case, consider how to model a fish
that ingests zooplankton contaminated with a hydrocarbon. Having decided on the one-
compartment model, we have finished the first step of the model development. We pos-
tulate only two processes: absorption by ingestion and elimination by kidney excretion.
Let us suppose that the hydrocarbon is biotransformed completely. We treat the hydro-
carbon and its metabolite as a single compound. Thus, it is not eliminated until the meta-
bolite is excreted. Finally, let us assume that the metabolite is removed by the kidney by
glomerular filtration only and is not reabsorbed. Thus, the rate of excretion, r
e
, will be
negatively proportional to the concentration in the blood plasma:
r
e
¼k
e
C ð18:19Þ
where C is the concentration of hydrocarbon plus metabolite and k
e
is a coefficient related
to the renal clearance rate. Note that this mass transfer process can be formulated as a rate
instead of a flux. The same will be true for ingestion. The rate of absorption, r
a
, is the pro-
duct of the assimilation efficiency, a (the fraction of ingested toxicant that is absorbed),
the mas s of food ingested per unit time, W, and the average concentration of toxican t in
the food, C
f
(in units of mass of solute per unit mass of food):
r
a
¼ aWC
f
ð18:20Þ
This situation is shown schematically in Figure 18.8. Equations (18.19) and (18.20),
having units of [Mt
1
], must be multiplied by the volume before substitution into equa-
tion (18.13) along with equation (18.14). Canceling the volume yields
dC
dt
¼ aWC
f
k
e
C ð18:21Þ
758 FATE AND T RANSPORT OF TOXINS