
3.7 RANS EQUATIONS AND TURBULENCE MODELS 93
Anisotropy
Two-equation turbulence models (i.e. k–
ε
, k–
ω
and other similar models)
are incapable of capturing the more subtle relationships between turbulent
energy production and turbulent stresses caused by anisotropy of the normal
stresses. They also fail to represent correctly the effects on turbulence of
extra strains and body forces. The RSM incorporates these effects exactly,
but several unknown turbulence processes (pressure–strain correlations, tur-
bulent diffusion of Reynolds stresses, dissipation) need to be modelled, and
the computer storage requirements and run times are significantly increased
compared with two-equation models. In order to avoid the performance
penalty associated with the solution of extra transport equations in the RSM,
several attempts have been made to ‘sensitise’ two-equation models to the
more complex effects. The first method to incorporate sensitivity to normal
stress anisotropy was the algebraic stress model. Subsequently, the research
groups at NASA Langley Research Center (Speziale) in the USA and at
UMIST (Launder) in the UK have developed a number of non-linear two-
equation models. These models are discussed below.
Algebraic stress equation model
The algebraic stress model (ASM) represents the earliest attempt to find an
economical way of accounting for the anisotropy of Reynolds stresses with-
out going to the full length of solving their transport equations. The large
computational cost of solving the RSM is caused by the fact that gradients
of the Reynolds stresses R
ij
etc. appear in the convective C
ij
and diffusive
transport terms D
ij
of Reynolds stress transport equation (3.55). Rodi and
colleagues proposed the idea that, if these transport terms are removed or
modelled, the Reynolds stress equations reduce to a set of algebraic equations.
The simplest method is to neglect the convection and diffusion terms
altogether. In some cases this appears to be sufficiently accurate (Naot and
Rodi, 1982; Demuren and Rodi, 1984). A more generally applicable method
is to assume that the sum of the convection and diffusion terms of the
Reynolds stresses is proportional to the sum of the convection and diffusion
terms of turbulent kinetic energy. Hence
− D
ij
≈−[transport of k (i.e. div) terms]
= (− . S
ij
−
ε
) (3.78)
The terms in the brackets on the right hand side comprise the sum of the rate
of production and the rate of dissipation of turbulent kinetic energy from the
exact k-equation (3.42). The Reynolds stresses and the turbulent kinetic
energy are both turbulence properties and are closely related, so (3.78) is
likely not to be too bad an approximation provided that the ratio /k does
not vary too rapidly across the flow. Further refinements may be obtained by
relating the transport by convection and diffusion independently to the
transport of turbulent kinetic energy.
Introducing approximation (3.78) into the Reynolds stress transport
equation (3.55) with production term P
ij
(3.57), modelled dissipation rate
u
i
′u
j
′
u
i
′u
j
′
u
i
′u
j
′
k
D
E
F
Dk
Dt
A
B
C
u
i
′u
j
′
k
Du
i
′u
j
′
Dt
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