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using hypothesis tests
We still need to find a test statistic we can use in our hypothesis test, and 
as the number in the sample is large, this means that using the binomial 
distribution will be time consuming and complicated.
There are 100 people in the sample, and the proportion of  successes 
according to the drug company is 0.9. In other words, the number of  
successes follows a binomial distribution, where n = 100 and p = 0.9.
As n is large, and both np and nq are greater than 5, we can use  
X ~ N(np, npq) as our test statistic, where X is the number of  patients 
successfully cured. In other words, we can use
X ~ N(90, 9)
to approximate any probabilities that we may need. 
If  we standardize this, we get
This means that for our test statistic we can use 
Z = X - 90 
  Z ~ N(0, 1)
          3
Here we’re standardizing 
X ~ N(90, 9).
I get it. So our test 
statistic is the variable 
we use for our test.
You use the test statistic to work out probabilities 
you can use as evidence.
This means that we use Z as our test statistic, as we can easily use it to 
look up probabilities and see how unlikely the results of  our sample 
are given the claims of  the drug company. We substitute our value of  
80 in place of  X, so we can use it to find the probability of  80 or fewer 
being cured.
Use the normal to approximate the binomial in our test statistic
Z = X - 90
           9
    = X - 90
           3
We can use this because n is 
large, np > 5 and nq is large.
X is the number of patients 
cured, in our case 80.