
INDUCTANCE 35
i
switch
+
−
R
L
V
B
V
L
+
−
Figure 1.25 A simple R– L circuit with a switch.
opened. That is, the switch “arcs” and you get a little spark. Too much arc and
the switch can be burned out.
We can develop an equation that describes what happens when an open switch
in the R–L circuit of Fig. 1.25 is suddenly closed. Doing so gives us a little
practice with Kirchhoff’s voltage law. With the switch closed, the voltage rise due
to the battery must equal the voltage drop across the resistance plus inductance:
V
B
= iR + L
di
dt
(1.49)
Without going through the details the solution to (1.49), subject to the initial
condition that i = 0att = 0, is
i =
V
B
R
1 − e
−
R
L
t
(1.50)
Does this solution look right? At t = 0, i = 0, so that’s OK. At t =∞, i =
V
B
/R. That seems alright too since eventually the current reaches a steady-
state, dc value, which means the voltage drop across the inductor is zero (v
L
=
Ldi/dt = 0). At that point, all of the voltage drop is across the resistor, so
current is i = V
B
/R. The quantity L/R in the exponent of (1.50) is called the
time constant, τ .
We can sketch out the current flowing in the circuit of Fig. 1.25 along with
the voltage across the inductor as we go about opening and closing the switch
(Fig 1.26). If we start with the switch open at t = 0
−
(where the minus suggests
just before t = 0), the current will be zero and the voltage across the inductor,
V
L
will be 0 (since V
L
= Ldi/dt and di/dt = 0).
At t = 0, the switch is closed. At t = 0
+
(just after the switch closes) the
current is still zero since it cannot change instantaneously. With zero current, there
is no voltage drop across the resistor (v
R
= iR), which means the entire battery
voltage appears across the inductor (v
L
= V
B
). Notice that there is no restriction
on how rapidly voltage can change across an inductor, so an instantaneous jump
is allowed. Current climbs after the switch is closed until dc conditions are
reached, at which point di/dt = 0sov
L
= 0 and the entire battery voltage is
dropped across the resistor. Current i asymptotically approaches V
B
/R.