
9.6 Gaussian Beams in Quadratic Index Media 609
In media with an imaginary quadratic index profile the Gaussian beam
can propagate steadily, and the amplitude is amplified. Because the energy
is confined in the region near the axis, we can call it a waveguide with gain.
From (9.177) we know that the larger the value of α
0
h, the smaller the beam
radius. The phase front is a spherical surface with a constant radius instead
of a plane, and this is an important difference between gain waveguides and
refractive-index waveguides. In the refractive-index waveguides the index is
higher near the axis, so the phase delay is greater, which counteracts the
phase advance near the beam axis in a Gaussian beam, and this results in
a plane phase front and a steady beam radius. In the gain waveguides, the
beam does not spread because of the higher gain near the axis, so the phase
front is a spherical surface. In practical applications pure gain waveguides do
not often exist, instead the gain and index waveguides exist simultaneously.
9.6.4 Steady-State Hermite-Gaussian Beams in
Medium with a Quadratic Index Profile
In homogeneous media, the Hermite-Gaussian beams are approximate solu-
tions of the Helmholtz equation within the paraxial condition, but for the
steady-state solutions in quadratic-index media the paraxial condition is un-
necessary. We can derive the exact solutions directly from the wave equation.
The solution is assumed to be
ψ = A
0
u(x, y)e
−jβz
, (9.181)
where A
0
is a constant and β is a complex propagation constant. Substituting
(9.181) into (9.140), we obtain
∂
2
u
∂x
2
+
∂
2
u
∂y
2
+ k
2
0
˙n
2
0
£
1 − Γ
2
¡
x
2
+ y
2
¢¤
u − β
2
u = 0. (9.182)
With the substitution that u = P (x)Q(y), (9.182) becomes
1
P (x)
d
2
P (x)
dx
2
+
1
Q(y)
d
2
Q(y)
dy
2
+ k
2
0
˙n
2
0
− k
2
0
˙n
2
0
Γ
2
¡
x
2
+ y
2
¢
− β
2
= 0. (9.183)
(9.183) is divided into two equations
1
P (x)
d
2
P (x)
dx
2
+ k
2
0
˙n
2
0
− β
2
− σ − k
2
0
˙n
2
0
Γ
2
x
2
= 0, (9.184)
1
Q(y)
d
2
Q(y)
dx
2
+ σ − k
2
0
˙n
2
0
Γ
2
y
2
= 0, (9.185)
where σ is a constant. Making the argument substitution that
ξ =
p
k
0
˙n
0
Γ x, η =
p
k
0
˙n
0
Γ y, (9.186)