
7.8 Coupling of Modes 451
Let a(z) denote the complex quantity of any field component of a desired
mode propagating in the z direction in a guided-wave system with spatial
dependence e
−jβ
0
z
. The normal mode form of the transmission-line equation
is
da
dz
= −jβ
0
a. (7.204)
Consider two modes a(z) and b(z), which, in the absence of coupling, have
natural phase constants β
01
and β
02
, respectively. We have the normal mode
representation of the transmission line equations for the two modes:
da
dz
= −jβ
01
a,
db
dz
= −jβ
02
b. (7.205)
The modes are assumed to be lossless, so that both β
01
and β
02
are real. If
β
01
and β
02
are positive, the phase velocities of both modes are in the +z
direction; if β
01
and β
02
are negative, the phase velocities of both modes
are in the −z direction; and if β
01
and β
02
are of opposite sign, the phase
velocities are in opposite directions.
We will see later that only the modes with analogous phase velocities can
have effective coupling, so we can neglect all other modes and obtain sim-
ple coupled-wave equations that describe the interaction. If the two guided
modes with effective coupling are a and b, some of the energy in mode a is
transferred to mode b and some of the energy in mode b is transferred to
mode a. Then the coupled-mode equations can be written as
da
dz
= −jβ
01
a + κ
12
b, (7.206)
db
dz
= −jβ
02
b + κ
21
a, (7.207)
where κ
12
and κ
21
, in general, are mutual coupling differential operators.
For weak coupling, κ
12
and κ
21
become complex coupling coefficients and
κ
12
and κ
21
are small compared with β
01
and β
02
, so the equations become
linear equations. The coupling is assumed to b e uniform over the length of
the coupling, so that κ
12
and κ
21
are independent of z.
For a source-free and lossless system, power conservation requires that
the total average power of the two modes must be independent of z, i.e.,
|a|
2
± |b|
2
= constant,
d
dz
¡
|a|
2
± |b|
2
¢
= 0. (7.208)
If the waves carrying power travel in the same direction for the two uncoupled
modes, the plus sign is to be taken, whereas if the waves carrying power travel
in opposite directions for the two uncoupled modes, the minus sign is to be
taken. Then we have
d|a|
2
dz
±
d|b|
2
dz
=
daa
∗
dz
±
dbb
∗
dz
=a
da
∗
dz
+ a
∗
da
dz
± b
db
∗
dz
± b
∗
db
dz
= aκ
∗
12
b
∗
+ a
∗
κ
12
b ± bκ
∗
21
a
∗
± b
∗
κ
21
a = 0.